Trigonometry Formulas by FehrmanTD@aol.COM RIGHT TRIANGLES | \ Sides: a, b, c | B \ Angles: A, B, C c | \ a | \ A = 90° |_A_____C_\ b SIDES FORMULAS find a (b sq + c sq)sq find a c x cosec. C c / sin C find a c x secant B c / cosine B find a b x cosec B b / sine B find a b x secant C b / cosine C find b (a sq - c sq)sq find b a x sine B a / cosec B find b a x cosine C a / secant C find b c x tan B c / cotan B find b c x cotan C c / tan C find c (a sq - b sq)sq find c a x cosine B a / secant B find c a x sine C a / cosec C find c b x cotan B b / tan B find c b x tan C b / cotan C ANGLES FORMULAS find C c/a = sine C 90°-B find C b/a = cosine C 90°-B find C c/b = tan C 90°-B find C b/c = cotan C 90°-B find C a/b = secant C 90°-B find C a/c = cosec C 90°-B find B b/a = sine B 90°-C find B c/a = cosine B 90°-C find B b/c = tan B 90°-C find B c/b = cotan B 90°-C find B a/c = secant B 90°-C find B a/b = cosec B 90°-C ------------------------------------- OBLIQUE TRIANGLES / \ / A \ b / \ c / \ /_C__________B_\ a TO FIND KNOWN SOLUTION C A-B 180°-(A+B) b a-B-A (a x sin B) / sin A c a-A-C (a x sin C) / sin A tan A a-C-b (a x sin C) / (b-(a x cos C)) B A-C 180°-(A+C) sin B b-A-a (b x sin A) / a A B-C 180°-(B + C) cos A a-b-c (b sq + c sq + a sq) / (2bc) sin C c-A-a (c x sin A) / a cot B a-C-b ((a x cscC) / b) - cot C c b-C-B b x sin C x cscB
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